Place the digits 1 to 8 into the vertices of a cube so that the sum of the digits on each cube's face is the same.
If neighboring digits, like 1 and 2 are placed in the diagonally opposite vertices of the cube, how many more such “neighbor“ pairs will be placed in the diagonally opposite vertices?
Explanations
All other “neighbor“ pairs will be in the diagonally opposite vertices as well.
The solution is shown in the diagram.